Solve linear systems using substitution method. Math 10-C Alberta mathematics.
Lesson 5.2 of Systems of Equations in Math 10C — Alberta curriculum lessons.
Definition — Substitution Method. The substitution method is an algebraic method of solving a system of equations by isolating one variable and substituting its expression into the other equation.
The big idea: if you can rewrite one equation as y = something (or x = something), you can plug that expression into the other equation. That gives you one equation with only one variable — which you already know how to solve.
Before You Start. Number your equations ① and ② before you begin so you can track which equation you are working with at each step.
The 4 Steps of Substitution. Step 1 — Isolate one variable.
Solve for x or y in one of the equations.
Step 2 — Substitute and solve.
Plug that expression into the other equation. Now you have one equation with one variable — solve it.
Step 3 — Back-substitute.
Take the value you just found and substitute it back in to find the other variable.
Step 4 — Write the ordered pair.
State the answer as an ordered pair (x, y) that satisfies both original equations.
Tip — Which Variable Should You Isolate?. Before starting, look at both equations.
Pick the variable that has a coefficient of 1 or -1 — isolating it will not introduce any fractions and keeps the arithmetic clean.
If no variable has a coefficient of 1 or -1, you may end up working with fractions (which is fine — just be careful).
Example 1 — Solve the System. ① 4x + 5y = 26
② 3x = y - 9
Solution. Step 1 — Isolate a variable.
Equation ② is almost solved for y already. Add 9 to both sides:
3x + 9 = y
So y = 3x + 9.
Step 2 — Substitute (3x + 9) for y in equation ①.
4x + 5(3x + 9) = 26
4x + 15x + 45 = 26
19x + 45 = 26
19x = 26 - 45
19x = -19
x = -1
Step 3 — Plug x = -1 back into y = 3x + 9.
y = 3(-1) + 9
y = -3 + 9
y = 6
Step 4 — Write the ordered pair.
Solution: (-1, 6)
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