Solve linear systems using substitution method. Math 10-C Alberta mathematics.
Lesson 5.2 of Systems of Equations in Math 10C: Alberta curriculum lessons.
Definition: Substitution Method. The substitution method is an algebraic method of solving a system of equations by isolating one variable and substituting its expression into the other equation.
The big idea: if you can rewrite one equation as y = something (or x = something), you can plug that expression into the other equation. That gives you one equation with only one variable, which you already know how to solve.
Before You Start. Number your equations ① and ② before you begin so you can track which equation you are working with at each step.
The 4 Steps of Substitution. Step 1: Isolate one variable.
Solve for x or y in one of the equations.
Step 2: Substitute and solve.
Plug that expression into the other equation. Now you have one equation with one variable. Solve it.
Step 3: Back-substitute.
Take the value you just found and substitute it back in to find the other variable.
Step 4: Write the ordered pair.
State the answer as an ordered pair (x, y) that satisfies both original equations.
Tip: Which Variable Should You Isolate?. Before starting, look at both equations.
Pick the variable that has a coefficient of 1 or -1, isolating it will not introduce any fractions and keeps the arithmetic clean.
If no variable has a coefficient of 1 or -1, you may end up working with fractions (which is fine, just be careful).
Example 1: Solve the System. ① 4x + 5y = 26
② 3x = y - 9
Solution. Step 1: Isolate a variable.
Equation ② is almost solved for y already. Add 9 to both sides:
3x + 9 = y
So y = 3x + 9.
Step 2: Substitute (3x + 9) for y in equation ①.
4x + 5(3x + 9) = 26
4x + 15x + 45 = 26
19x + 45 = 26
19x = 26 - 45
19x = -19
x = -1
Step 3: Plug x = -1 back into y = 3x + 9.
y = 3(-1) + 9
y = -3 + 9
y = 6
Step 4: Write the ordered pair.
Solution: (-1, 6)
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