Learn formulas and calculations for spheres. Math 10-C Alberta mathematics.
Lesson 1.5 of Measurement in Math 10C — Alberta curriculum lessons.
Sphere — Key Definition. A sphere is the set of all points in space that are the same distance from a centre point — like a perfectly round ball.
That fixed distance is called the radius r.
The distance all the way across the sphere through the centre is the diameter d = 2r.
Strategy: Both Formulas Use the Radius. Both sphere formulas require the radius, not the diameter.
If a problem gives you the diameter, your first step is always:
r = (d)/(2)
Imagine wrapping a cylinder snugly around a sphere — same radius, and tall enough that the sphere just fits inside. The cylinder's height equals the sphere's diameter, which is 2r.
Derivation — Where SA = 4πr² Comes From. It turns out the sphere's surface area equals the curved (lateral) area of that surrounding cylinder.
The lateral area of the cylinder is circumference times height:
Step 1: Lateral area = 2π r × 2r
Step 2: Simplify:
A = 4π r^2
A sphere's volume is exactly (2)/(3) of the cylinder that surrounds it (radius r, height 2r).
Derivation — Where V = (4/3)πr³ Comes From. Step 1: Volume of the cylinder = π r^2 × 2r = 2π r^3
Step 2: The sphere holds (2)/(3) of that cylinder:
V = (2)/(3) × 2π r^3
Step 3: Simplify:
V = (4)/(3)π r^3
Memory Tip — r² vs. r³. Surface area uses r^2 (area is two-dimensional).
Volume uses r^3 (volume is three-dimensional).
If a question gives the diameter, halve it to get r before doing anything else.
A satellite is wrapped in polyester film. How much film is needed to cover the Echo Satellite, which has a circumference of 95.8 m?
Strategy — Find Radius First. The problem gives the circumference, not the radius.
Use C = 2π r to solve for r first, then apply SA = 4π r^2.
Solution. Step 1: Use C = 2π r to find the radius:
95.8 = 2π r
r = (95.8)/(2π)
r = (95.8)/(6.283)
r ≈ 15.2 m
Step 2: Now use SA = 4π r^2:
SA = 4π(15.2)^2
SA = 4π(231.04)
Answer: SA ≈ 2903.3 m^2 of film is needed.
Key Tip. When a sphere problem gives the circumference instead of the radius, C = 2π r is your way in.
Find r first, then go to the SA or volume formula.
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