Find sums of infinite geometric series using convergence. Math 20-1 Alberta curriculum.
Lesson 3.5 of Sequences and Series in Math 20-1: Alberta curriculum lessons.
Infinite Sequence and Series. An infinite sequence is a sequence with an unlimited number of terms: t_1, t_2, t_3,
An infinite geometric series is a geometric series that goes on forever: t_1 + t_2 + t_3 +
For example, the series 4 + 2 + 1 + 0.5 + 0.25 + never stops. The + means we keep adding terms indefinitely.
Let's see what happens to the partial sums of two different infinite geometric series.
Series 1: 4 + 2 + 1 + 0.5 + 0.25 + where t_1 = 4, r = (1)/(2). S_4 = 4 + 2 + 1 + 0.5 = 7.5
S_6 = 4 + 2 + 1 + 0.5 + 0.25 + 0.125 = 7.875
S_7 = 7.9375
S_75 ≈ 8 (using the formula)
S_100 ≈ 8 (using the formula)
The partial sums get closer and closer to 8. Even at S_75 and S_100, the result rounds to 8. The series settles on a fixed value.
Series 2: 4 + 8 + 16 + 32 + 64 + where t_1 = 4, r = 2. S_4 = 4 + 8 + 16 + 32 = 60
S_6 = 252
S_7 = 508
S_20 = 4 194 300
S_30 = 4 294 967 292
The partial sums grow without bound. They keep getting bigger forever. The series does NOT settle on any fixed value.
Why the Difference?. The difference comes down to r, the common ratio.
In Series 1, r = (1)/(2). Each term is smaller than the one before. The added pieces shrink toward zero, so the total approaches a limit.
In Series 2, r = 2. Each term is bigger than the one before. The added pieces grow without bound, so the total explodes.
Part a) 0.5 - 1 + 2 - 4 + . Step 1: Find r:
r = (-1)/(0.5) = -2
Step 2: Check the condition:
|r| = |-2| = 2, which is greater than 1.
This series is divergent, no infinite sum exists.
Part b) 12 + 3 + (3)/(4) + . Step 1: Find r:
r = (3)/(12) = (1)/(4)
Step 2: Check the condition:
|r| = (1)/(4), which is less than 1.
This series is convergent, an infinite sum exists.
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