Solve and graph quadratic inequalities in two variables. Math 20-1 Alberta.
Lesson 2.7 of Linear Functions & Systems of Equations in Math 20-1 — Alberta curriculum lessons.
Definition — Quadratic Inequality in Two Variables. A quadratic inequality in two variables has one of these four forms:
y < ax^2 + bx + c
y > ax^2 + bx + c
y ≤ ax^2 + bx + c
y ≥ ax^2 + bx + c
Solving the inequality means determining a solution region — the set of all (x, y) pairs that make the statement true. This region lies above or below the parabola, and may or may not include the points on the parabola itself.
The Solution Is a Shaded Graph. Unlike a quadratic equation (which gives a curve), a quadratic inequality gives a shaded region. Every point in the shaded region satisfies the inequality. Every point outside does not.
The Test-Point Method. Before graphing, it helps to verify individual points. To test whether an ordered pair (x, y) is a solution:
Step 1: Substitute the x and y values of the point into the inequality.
Step 2: Simplify the right side.
Step 3: Decide whether the resulting statement is TRUE or FALSE. A true statement means the point IS in the solution region.
Test each of these points: (0, 0), (2, -2), (7, 1), (-5, -2), (-3, 0), (1, 4).
Test (0, 0). 0 ≥ (0)^2 - 3(0) - 4
0 ≥ -4 TRUE
Test (2, -2). -2 ≥ (2)^2 - 3(2) - 4
-2 ≥ 4 - 6 - 4
-2 ≥ -6 TRUE
Test (7, 1). 1 ≥ (7)^2 - 3(7) - 4
1 ≥ 49 - 21 - 4
1 ≥ 24 FALSE
Test (-5, -2). -2 ≥ (-5)^2 - 3(-5) - 4
-2 ≥ 25 + 15 - 4
-2 ≥ 36 FALSE
Test (-3, 0). 0 ≥ (-3)^2 - 3(-3) - 4
0 ≥ 9 + 9 - 4
0 ≥ 14 FALSE
Test (1, 4). 4 ≥ (1)^2 - 3(1) - 4
4 ≥ 1 - 3 - 4
4 ≥ -6 TRUE
Summary. Solutions: (0, 0), (2, -2), and (1, 4) all make the inequality true.
Non-solutions: (7, 1), (-5, -2), and (-3, 0) make the inequality false — they lie outside the solution region.
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