Factor polynomials and apply factor theorem. Math 30-1 Alberta Grade 12.
Lesson 2.3 of Polynomial Functions in Math 30-1 — Alberta curriculum lessons.
Factoring is the process of breaking down a polynomial into a product of simpler polynomials. Think of it as the reverse of multiplying polynomials together. Just like you can break down the number 12 into 3 × 4, you can break down polynomials into their "building blocks."
Why is factoring called "un-multiplying"?. Factoring takes us backwards from the expanded form to the factored form!
Factoring is one of the most powerful tools in algebra because it helps us:
1. Find X-Intercepts (Zeros/Roots). When a polynomial is factored, finding where it equals zero becomes easy! If f(x) = (x + 2)(x - 3), then f(x) = 0 when x = -2 or x = 3.
2. Solve Polynomial Equations. Instead of solving x^2 + 5x + 6 = 0 (difficult!), we can factor to get (x + 2)(x + 3) = 0, then use the Zero Product Property: if a product equals zero, at least one factor must be zero.
3. Simplify Rational Expressions. Factoring allows us to cancel common factors in fractions like:
4. Graph Polynomial Functions. Factored form immediately tells us where the graph crosses the x-axis and helps us sketch the curve.
5. Solve Real-World Problems. From projectile motion to area problems, factoring helps us find practical solutions.
Question. Is (x + 2) a factor of f(x) = x^3 + 5x^2 + 2x - 8?
Step 1: Understand what we're testing. We want to know if (x + 2) divides evenly into x^3 + 5x^2 + 2x - 8.
Step 2: Calculate f(-2). f(x) = x^3 + 5x^2 + 2x - 8
Calculate each term carefully:.
Now add them all:.
Step 3: Interpret the result. Since f(-2) = 0, by the Factor Theorem, (x + 2) IS a factor of f(x).
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