Laws of Logarithms

Solve logarithmic equations and check solutions. Math 30-1 Alberta Grade 12.

Lesson 3.7 of Exponents & Logarithms in Math 30-1 — Alberta curriculum lessons.

What you'll learn in this lesson

Inside the lesson — a free preview

Why We Need Log Laws

Breaking Down Complex Logs. When logs have products, quotients, or powers inside, you can't evaluate them directly. The three laws let you expand or collapse these expressions. Both directions are tested on exams.

The Critical Order of Operations Rule

⚠️ Order Matters. • Coefficients must be +1 or −1 before combining logs

• If you have 2log(x) or 3log(y), use Power Law first

• Rule: Power Law → then Product or Quotient Law

Important Warnings — What Log Laws Are NOT

These are among the most common errors students make:

❌ Common Error #1. (x + y) ≠ (x) + (y) — the Product Law only applies to multiplication inside the argument, never addition.

❌ Common Error #2. (x - y) ≠ (x) - (y) — the Quotient Law only applies to division inside the argument, never subtraction.

❌ Common Error #3. ((x))/((y)) ≠ ((x)/(y)) — you cannot combine two separate logs that are being divided unless they share the same base AND you are using the change of base formula (covered later).

❌ Common Error #4. ( x)^2 ≠ (x^2) — an exponent on the entire log expression is not the same as an exponent inside the argument. The Power Law moves an exponent from inside to outside, not the other way around.

Worked example: a: Combining Logs Into a Single Logarithm

Question: Simplify _2(24) - _2(3)

Solution. Step 1: Identify

Both logs already have coefficient 1, so no Power Law needed.

Step 2: Apply Quotient Law

Subtract means divide the arguments:

_2(24) - _2(3) = _2((24)/(3)) = _2(8)

Step 3: Evaluate

What power gives 8?

2^3 = 8 → answer = 3

✓ Verify: _2((24)/(3)) = _2(8) = 3 ✓

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