Analyze and transform radical functions including domain/range. Math 30-1.
Lesson 6.1 of Radical & Rational Functions in Math 30-1 — Alberta curriculum lessons.
Definition. A radical equation is any equation where the variable appears inside a square root (or other radical).
For example: √(12 - x) + 4 = 7 is a radical equation because x is trapped inside the square root.
The Challenge. You can't just "move things around" like a normal equation — the square root gets in the way.
The big idea is: square both sides to eliminate the radical.
But this creates a risk: squaring can produce fake answers called extraneous roots, so you must always check your answer.
⚠️ Remember: you are squaring sides, NOT terms!. (√(12-x) + 4)^2 ≠ (12-x) + 16 ← this is WRONG
You must isolate the radical first.
Question. State any restrictions, then algebraically find all roots.
Step 1 — State the Restriction. The expression under the square root must be ≥ 0:
12 - x ≥ 0
-x ≥ -12
x ≤ 12
So x must be 12 or less.
Step 2 — Isolate the Radical. Subtract 4 from both sides:
7 - 4 = √(12 - x)
3 = √(12 - x)
The radical is now alone on the right side.
Step 3 — Square Both Sides. (3)^2 = (√(12 - x))^2
9 = 12 - x
Notice: because the radical was isolated first, squaring it simply removes it cleanly.
Step 4 — Solve for x. 9 - 12 = -x
-3 = -x
x = 3
Step 5 — Check the Restriction. Is x = 3 ≤ 12? Yes ✓
Step 6 — Verify in the Original Equation. 7 = √(12 - 3) + 4
7 = √(9) + 4
7 = 3 + 4
7 = 7 ✓
Complete Summary. Original equation: 7 = √(12 - x) + 4
Restriction: x ≤ 12
Solution: x = 3
Verified: both sides equal 7 ✓
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