Understand sine, cosine, tangent, and reciprocal ratios. Math 30-1 Alberta.
Lesson 4.3 of Trigonometric Ratios & Functions in Math 30-1 — Alberta curriculum lessons.
Trigonometric ratios describe relationships between the sides of a right triangle relative to an angle θ.
Primary Trigonometric Ratios. θ = (opposite)/(hypotenuse)
θ = (adjacent)/(hypotenuse)
θ = (opposite)/(adjacent)
A common memory trick to remember the trigonometric ratios is:
SOH CAH TOA
SOH → = (Opposite)/(Hypotenuse)
CAH → = (Adjacent)/(Hypotenuse)
TOA → = (Opposite)/(Adjacent)
Each primary trig ratio has a reciprocal:
Reciprocal Trigonometric Ratios. θ = (hypotenuse)/(opposite) (cosecant)
θ = (hypotenuse)/(adjacent) (secant)
θ = (adjacent)/(opposite) (cotangent)
As Reciprocals. These can also be written as:
θ = (1)/(θ)
θ = (1)/(θ)
θ = (1)/(θ)
Tangent and cotangent can also be written as quotients of sine and cosine:
θ = (θ)/(θ)
θ = (θ)/(θ)
Suppose the terminal arm of angle θ passes through a point:
P(x, y)
Let:
r = √(x^2 + y^2)
where r is the distance from the origin to point P.
On the Unit Circle, the radius is:
r = 1
So the coordinates of a point on the circle can be written as:
(x, y) = (θ, θ)
The signs of trigonometric ratios depend on the quadrant in which the angle lies.
Since we know that on the unit circle:
• θ = y
• θ = x
• θ = (y)/(x)
The signs of x and y in each quadrant determine which ratios are positive or negative.
Example 1: Find 90°
Solution: At 90°, the coordinate is (0, 1)
Since θ = y, we have:
90° = 1
Example 2: Find 180°
Solution: At 180°, the coordinate is (-1, 0)
Since θ = x, we have:
180° = -1
Example 3: Find 0°
Solution: At 0°, the coordinate is (1, 0)
Since θ = (y)/(x), we have:
0° = (0)/(1) = 0
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